MODERN PHYSICS

A photon emitted from an excited hydrogen atom has an energy of 3.02 electron volts. Which electron energy-level transition would produce this photon?

A. n=1 to n=6

B. n=2 to n=6

C. n=6 to n=1

D. n=6 to n=2

I chose B but the correct answer is D can someone tell me why? And what's the difference?

D. n=6 to n=2

Explanation:

Given;

energy of emitted photon, E = 3.02 electron volts

The energy levels of a Hydrogen atom is given as;  E = -E₀ /n²

where;

E₀ is the energy level of an electron in ground state =  -13.6 eV

n is the energy level

From the equation above make n, the subject of the formula;

n² = -E₀ / E

n² = 13.6 eV / 3.02 eV

n² = 4.5

n = √4.5

n = 2

When electron moves from higher energy level to a lower energy level it emits photons;

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2

Therefore,  The electron energy-level transition is from n = 6 to n = 2

the force required to move the cart is divided by three or 33.33 n.

true tan speed = ang vel x radius