A straight wire segment in a circuit is 30.0 m long and moves at 2.0 m/s perpendicular to

a magnetic field. The total resistance of the circuit is 5.0 22. What is the current?

O.12A

O 1.2A

0.122

O 1.20

PLEASE HELP

I = 12*B   (the information about B does not appear in the statement)

Explanation:

The motion of the segment of the circuit, in a constant magnetic field makes that opposite charges inside the segment separate of each other. This generate a induced potential difference at the ends of the segment that is given by the following formula:

  (1)

v: speed of the segment = 2.0m/s

B: magnitude of the magnetic field

 (2)

The induced current calculated by replacing the result of (2) in the following formula:

   (3)

Then, you only have to replace the value of the magnitude of the magnetic field B in (3) to calculate the current.

learn it on the intertant so you can solve

hey , the answer is c