Calculate the wavelength of light that has its third minimum at an angle of 30.0º when falling on double slits separated by 3.00~\mu\text{m}3.00 μm.

Given values:

As we know,

→

By putting the values, we get

By converting it to "nm", we get

Thus the response above is correct.  

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λ = 428.57 nm

Explanation:

Young's double slit experiment is described by the expression

          d sin θ = m λ                    constructive interference

          d sin θ = (m + ½) λ           destructive interference

where d is the distance between the slits, λ is the wavelength, m is an integer that describes the order of interference

In this case they give us the angle 30º, the distance between the slits d = 3.00 μm = 3.00 10⁻⁶ m and the order of interference m = 3; we use the destructive interference equation

         λ = d sin θ / (m + ½)

let's calculate

        λ = 3 10⁻⁶ sin 30 / (3 +1/2)

         λ = 4.2857 10⁻⁷ m

we reduce to nm

        λ = 4.2857 10⁻⁷ (10⁹ nm / 1 m)

         λ = 428.57 nm

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂