A ball of mass 1156 grams and density of 6.00× kg/ drops in water, if the density of water is 1.0kg/. determine the volume of water displaced by the ball?

The volume of water displaced by the ball is 1.156 m³

Explanation:

Given;

mass of the object, m = 1156 g = 1.156 kg

density of the object, ρ' = 6.00 × kg/m³

density of the fluid (water) ρ = 1.0 × kg/m³

From Archimedes law, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.

Buoyant force is given as;

Fb = ρVg = mg

Where;

Fb is the buoyant force

ρ is the density the fluid

V is the submerged volume

g is the acceleration due to gravity

m is mass of the object

The equation above can be reduced to;

ρV = m

V = m/ρ

V = 1.156/1

V = 1.156 m³

Thus, volume of the object (ball) submerged is equal to volume of the fluid (water) displaced = 1.156 m³