A charged particle of 5.1 nC and another with 2.6 nC are separated by a distance of 5.5 m. What is the electric potential energy between the particles?

The electric potential energy between the particles is 2.167 x 10⁻⁸ J

Explanation:

Given;

a charged particle, q₁ = 5.1 nC

another charged particle, q₂ = 2.6 nC

distance between the charged particle, r = 5.5 m

The electric potential energy between the charged particles is calculated as;

where;

is the electric potential energy between the particles

k is coulomb's constant = 8.99 x 10⁹ Nm²/c²

Substitute the given values and solve for electric potential energy;

Therefore, the electric potential energy between the particles is 2.167 x 10⁻⁸ J