1. How many calories of heat are required to raise the temperature of 550 g of water from 12.0°C to
18.0°C? (remember the specific heat of water is 1.00 cal/g x °C)

Q = 550 x 1 x (18-12) =3300

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation: