Copper wire #1 has a length L and a radius b. Copper wire #2 has a length 2L and a radius 2b. Which statement about the resistance across the ends of the wires is true? The resistance of wire #1 is four times higher than that of wire #2. The resistance of wire #1 is equal to that of wire #2. The resistance of wire #1 is twice as high as that of wire #2. The resistance of wire #1 is half that of wire #2.

The resistance of wire #1 is twice as high as that of wire

Explanation:

For resistance of a wire the formula is as follows

R = ρ l / s where  ρ is a constant called specific resistance , l is length and s is cross sectional area . If r be the radius of cross section

R = ρ l / π r²

For first wire , putting the given values in the equation

R₁ = ρ L/ π b²

For second wire,

R₂ = ρ 2L/ π 4b²

= 2

The resistance of wire #1 is twice as high as that of wire

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.