A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.30 Ω is in a 1.0 mT magnetic field, with the coil oriented for maximum flux. The coil is connected to an uncharged 3.0 μF capacitor rather than to a current meter. The coil is quickly pulled out of the magnetic field.

Afterward, what is the voltage across the capacitor?

The voltage across the capacitor = 0.8723 V

Explanation:

From the question, it is said that the coil is quickly pulled out of the magnetic field. Therefore , the final magnetic flux linked to the coil is zero.

The change in magnetic flux linked to this coil is:

    = 0 - BA cos 0°

Using Faraday's Law; the induced emf on N turns of coil is;

Also; the induced current I =

The voltage across the capacitor can now be determined as:

=

= 0.8723 V

answer: option c.

explanation:

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27