A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string is submerged in the water, but does not touch the bottom. What are the tension in the string and? a. Find the tension in the string. (10pts) b. What is the new balance reading? (10pts)A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string is submerged in the water, but does not touch the bottom. What are the tension in the string and? a. Find the tension in the string. (10pts) b. What is the new balance reading? (10pts)

a  

The tension in the string is  

 b

 The new balance reading is  

Explanation:

From the question we are told that

    The mass of the beaker of water is  

     The diameter of the copper ball is  

There are two forces acting on the copper ball

   The first is the Buoyant force of the water pushing it up which is mathematically represented as

Where is the density of water which has value of  

            g is the acceleration due to gravity

          is the volume of water displaced by the copper ball  which is mathematically evaluated as

The radius r is  

Substituting value  

   Substituting for  F

     The second force is the weight of the copper ball which is mathematically represented as

Now m is the mass which can be mathematically evaluated as

Where  is the density of copper with  value of  

So      

So the weight of copper is  

Now the tension the string would be mathematically evaluated as

So        

From this value we that the string is holding only 0.85 N of the copper weight thus (0.956 - 0.85 = 0.1065 N ) is being held by the balance

Now the mass equivalent of this weight is mathematically evaluated as

Converting to grams  

So the new balance reading is  

vapour or gas assuming atmospheriv pressure

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2