A certain pair of slits are separated by a distance d. Monochromatic coherent light falls on this pair of slits and the interference pattern is observed on a screen. The separation distance between adjacent bright fringes near the center of that interference pattern on the screen is found to be 2.0 mm. Then the slits are replaced by another pair of slits; these slits are separated by a distance one-half that of the original pair. The interference pattern is again observed. What is the new separation distance between adjacent bright fringes

The new separation distance between adjacent bright fringes will be 4 mm

Explanation:

Since, the distance between adjacent bright fringes is given by the formula:

Δx₁ = λL/d = 2 mm   eqn (1)

where,

Δx = Distance between adjacent bright fringes

λ = wavelength of light = constant for both cases

L = Distance between the slits and the screen

d = slit separation

Now, for the second case:

Slit Separation = d/2

Therefore,

Δx₂ = λL/(d/2)

Δx₂ = 2(λL/d)

using eqn (1), we get:

Δx₂ = 2 Δx₁

Δx₂ = 2(2 mm)

Δx₂ = 4 mm

multiply 2kg by latent heat of vap

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards