A concave mirror is shown with curvature positioned at 8 on a ruler that goes from 0 to 14 centimeters. The object is located at 4, and the focal point is located at 6.5.

If an object is placed 4 cm from a 1.5 cm focal length mirror, the image will be?

virtual, upright, and larger
virtual, inverted, and smaller
real, upright, and larger
real, inverted, and smaller

real, inverted, and smaller

Explanation:

If an object is placed 4 cm from a 1.5 cm focal length mirror, the image distance can be gotten using the mirror formula as shown.

1/f = 1/u+1/v

f is the focal length

u is the object distance

v is the image distance

Note that the image distance and focal length of the concave mirror are positive

Given:

u = 4cm

f = 1.5cm

1/v = 1/1.5-1/4

1/v = 0.67-0.25

1/v = 0.42

v = 1/0.42

v = 2.38cm

since the image distance value is positive, the image is a REAL and INVERTED image.

To determine whether it is magnified or diminished, we will find its magnification. If magnification is greater than 1, it is magnified but if less than 1, it is diminished.

Magnification = v/u

Magnification = 2.38/4

Magnification = 0.595 or. 0.6

Since the magnification is less than one, the image is DIMINISHED (SMALLER).

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