A scuba diver measures an increase in pressure of around 10^5 Pa upon descending by 10 m, what is the change in force per square centimetre on the diver’s body?

Explanation:

Given that,

The pressure around the diver is

P = 10^5 Pa,

At a height of 10m

h = 10m

We want to find the force per square centimeter of the diver body

Pressure = force / Area

Force / Area = pressure,

And since the pressure is given

Then,

Force / Area = 10^5 Pa

Since 1 pascal = 1 N/m²

Force / Area = 10^5 N/m²

Since, we know that, 100cm = 1m

(100cm)² = (1m)²

10000cm² = 1m²

10⁴cm² = 1m²

Then,

Force / Area = 10^5 N/m² × 1m²/10⁴cm²

Force / Area = 10 N/cm²

The required force per unit area is 10 N /cm²

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

it has to be b, about 97 percent.