A 6.72 particle moves through a region of space where an electric field of magnitude 1270 N/C points in the positive direction, and a magnetic field of magnitude 1.15 T points in the positive direction. If the net force acting on the particle is 6.13E-3 N in the positive direction, calculate the magnitude of the particle's velocity. Assume the particle's velocity is in the - plane.

Explanation:

Using:

Force = electric field * charge

Force = magnitude of charge * velocity * magnetic field * sin tither

Force on particle due to electric field:

Force on particle due to magnetic field:

is in the positive x direction as is in the negative x direction while net force is in the positive x direction.

Magnetic field is in the positive Z direction, net force is in the positive x direction.

According to right hand rule, Force acting on particle is perpendicular to the direction of magnetic field and velocity of particle. This would mean the force is along the y-axis. As this is a negatively charged particle, the direction of the velocity of the particle is reversed. Therefore velocity of particle, v, has to be in the negative y direction.

Now,

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this