What is the magnitude of the rate of change of the magnetic field inside the coil? You will need to calculate this algebraically before you can get a number. Write an expression for the magnetic field due to the wire at the location of the coil. Use the approximate formula, since the wire is very long. Remember the chain rule, and remember that ⅆ ⅆ .

The answer to this questions are, (a) 0.685 * 10^-4 T/sec (b) 0.946 * 10^-6V

Explanation:

Solution

Recall

radius r = 0.02m

N = 11 turns

Instant I = 3 amperes

Velocity v =3.3m/s

x = 0.17 m

(a) What is the magnitude of the rate of change of the magnetic field inside the coil

db/dt =μ₀T/2π x²

Thus,

= 4π * 10^-7* 3* 3.3/2π * 0.17²

=685.12* 10^-7

which is now,

0.685 * 10^-4 T/sec

(b) What is the magnitude of the voltmeter reading.

μ =  N (db/dt)πr²

Note: this includes all 11 turns of the coil

Thus,

= 11 * 0.6585* 10^-4* 3.14 * (0.02)²

= 946 * 10^-7

which is = 0.946 * 10^-6V

Note: Kindly find an attached copy or document of the complete question of this exercise

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.

high-sugar diet and high cholesterol