I'm not asking a question, instead I'm answering two different ones, the first being:
A large boulder falls from a cliff located 1,044 meters away from a herd of elephants. The temperature of the air is 29°C. How long after the boulder crashes will the elephants hear the sound?
3.20 sec
3.00 sec
0.30 sec
30 sec
Ok, so first we need to find how fast sound travels in 29 degrees celsius
To find this we use the formula:
VT=331 m/s+0.6 m/s (29 degrees celsius)= 348.4 m/s
Now that we know the speed we can finish the problem
Since velocity=distance/time, time=distance/velocity
1,044 meters/348.4 m/s= 2.99 seconds, or approximately 3 seconds.

Next question:
A large boulder falls from a cliff located 1,044 kilometers away from a herd of elephants. The temperature of the air is 29°C. At what rate does the sound of the crashing boulder travel toward the elephants?
331 m/s
334 m/s
36 m/s
348 m/s

We answered this in the first part of the other question;
VT= 331 m/s +0.6 m/s (29 degrees celsius) = 348.4 m/s which is approximately 348 m/s

I got both of these answers right, let me know if you need further clarification, hope this helps whoever need it! You got this!! : )

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

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