Describe how the phase angle changes as you move from below resonance to above resonance Based on your results here and other textbook resources, what will happen if your frequency is much lower than resonance? What about much larger?

Answer

Explanation:

In a LCR Circuit, the phase difference between voltage and current is usually summarized as;

tan∅ = XL- XC

               R

     =WL - 1/WC

            R

When w=0 ( i.e when it is very low)    tan∅ = ∞

                                                         or      ∅ = -90

When w=0 ( i.e when it is very large)    tan∅ =+ ∞

                                                         or         ∅ = +90

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min