One contraction cycle in muscle requires 67 kJ , and the energy from the combustion of glucose is converted with an efficiency of 45% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number.

19 contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose.

Explanation:

Complete Question

Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol.

One contraction cycle in muscle requires 67 kJ, and the energy from the combustion of glucose is converted with an efficiency of 45% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole of glucose? Round your answer to the nearest whole number.

Complete combustion of glucose liberates 2870 kJ/mol.

Complete combustion of one mole of glucose will liberate 2870 × 1 = 2870 kJ

The energy from the combustion of glucose is converted with an efficiency of 45% to contraction.

So, the amount of energy from the combustion of one mole of glucose that is converted to contraction is

45% × 2870 = 1,291.5 kJ

One contraction cycle requires 67 kJ of energy, so, 1291.5 kJ will cause

(1291.5/67) contraction cycles = 19.28 contraction cycles = 19 contraction cycles to the nearest whole number.

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