Investigate the chemical potential μ upon a change in volume. We will use the fact that
F=U−TS and μ=∂F∂N. We will compute μ(Vf)−μ(Vi)

Take N=20 moles (which is 20 times Avagodro's number of particles), T=300 K, Vi=0.01 m^3,Vf=0.02 m^3
For a gas with an excluded volume: U=32NkT+const S=Nkln⁡(V−bN)+const

If b=9 × 10-29 m^3, compute µ(Vf)- µ(Vi)

Explanation:

Let's rewrite F in terms of N.

C is a constant value.

We know that the chemical potential μ is the partial derivative of F with respect to N.

We can find now the chemical potential μ(Vf).

We can do the same to find μ(Vi).

Therefore µ(Vf) - µ(Vi) will be:

I hope it helps you!

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

answer(20) psi;