The dissociation energy of a molecule is the energy required to break apart the molecule into its separate atoms. The dissociation energy for a particular molecule is 1.12 × 10-18 J. Suppose that this energy is provided by a single photon.

Determine the (a) wavelength and (b) frequency of the photon. (c) In what region of the electromagnetic

(a) 1.78 * 10^(-7) m

(b) 1.69 * 10(15) Hz

(c) Ultraviolet light

Explanation:

(a) To determine the wavelength, we use one of the formulae of energy of a wave:

E = hc/λ

Where h = Planck's constant

c = speed of light

λ = wavelength.

Therefore, wavelength, λ, is:

λ = hc/E

λ = (6.626 * 10^(-34) * 3 * 10^8) / (1.12 * 10^(-18))

λ = 1.775 * 10^(-7) m

This is the wavelength of the photon.

(b) Using formula for speed of a wave, we can find the frequency:

c = λf

Where f = frequency.

f = c/λ

f = (3 * 10^8) / (1.775 * 19^(-7))

f = 1.69 * 10^(15) Hz

This is the frequency of the photon.

(c) By comparing the frequency and wavelength of the photon with the electromagnetic spectrum, the proton is in the region of ultraviolet light.

d

explanation:

i think the answer is d. but im not sure!

volts times amps 6 x 0.5 3w