Can anyone check it?

block a weighs 1.40 n, and block b weighs 4.20 n. the coefficient of kinetic friction between all surfaces is 0.30. find the magnitude of the horizontal force necessary to drag block b to the left at constant speed if a and b are connected by a light, flexible cord passing around a fixed, frictionless pulley.

2.52 N

Explanation:

Since, Block B needs to be dragged at constant speed, it means net force on it would be zero. The tension T would  act in the string connecting the two blocks. Frictional force would act on both the contact surfaces of block B.

Refer to Free body diagram:

F - T - f₁ - f₂ = 0

⇒F =- T + f₁ + f₂

From block A,

Thus,

Inserting the values:

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .