If this person has a normal 8.00% ability to accommodate (increase) the power of his eyes, what is the maximum distance of objects he can see clearly in m with his contact lenses and with totally relaxed eyes? (Assume a lens-to-retina distance of 2.00 cm. If he can see very distant objects clearly, enter 'infinity'.)

This is what a calorimeter is used for simpler ex, to measure calories in food.

Ithink it is letter b, i may be wrong but i think that is the answer

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j