A cockroach of mass m lies on the rim of a uniform disk of mass 3.00 m that can rotate freely about its center like a merry-go-round. Initially the cockroach and disk rotate together with an angular velocity of 0.289 rad/s. Then the cockroach walks halfway to the center of the disk. (a) What then is the angular velocity of the cockroach-disk system? (b) What is the ratio K/K0 of the new kinetic energy of the system to its initial kinetic energy?

answer: (431,2)

step-by-step explanation:

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

higher potential

explanation:

because it is in a high speed so it must move into a of high potential