A ball m = 1.0 kg is dropped from a balcony A at 8.0 m above the ground. The ball is caught at point B at 4.00 m above the ground. Take the reference point of the zero gravitational potential energy configuration at the ground, such that Ug = 0 at y = 0. Take g = 9,8 m/s2. Calculate the work done by the conservative force Wg between A and B.

c) up is the direction the magnetic force is acting on the charge.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

i think the answer is a and b

i wish you luck