A 100100-watt [W] motor (6060% efficient) is available to raise a load 1010 meters [m] into the air. If the task takes 8080 seconds [s] to complete, how heavy was the load in units of kilograms [kg]?

m = 48.93kg

The load is 48.93kg.

Explanation:

Given;

Power P = 100watts

Efficiency e = 60% = 0.60

distance d = 10 m

time taken t = 80 s

Acceleration due to gravity g = 9.81m/s

Workdone W can be expressed as;

W = ePt = Fd = mgd

ePt = mgd

Making m the subject of formula;

m = ePt/gd

Substituting the values;

m = (0.60×100×80)/(9.81×10)

m = 48.93kg

The load is 48.93kg.

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