A sinusoidally oscillating current I ( t ) with an amplitude of 9.55 A and a frequency of 359 cycles per second is carried by a long, straight wire. A rectangular loop of copper wire with dimensions b = 72.2 cm by c = 32.5 cm is located a = 80.2 cm from the straight wire, and is coplanar with it. Calculate the average power P avg dissipated by the loop if its resistance is 64.3 Ω .

Explanation:

Given that;

I₀ = 9.55 A

f = 359 cycles/s

b = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Using the formula;

where;

Replacing our values into above equation; we have:

Then the is calculated as:

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)