A particle has a charge of 5.2x10^-19 coulombs and experience a force of 9.5x10^-15 Newton's when it travels through a magnetic field with strength 2.2 x 10^-1 telsa what is the speed of the particle

83000 m/s

Explanation:

Using

F = Bqv Equation 1

Where F = Force experienced by the charge, B = magnetic field q = charge of the particle, v = speed of the particle.

make v the subject of the equation

v = F/Bq Equation 2

Given: q = 5.2×10⁻¹⁹ Coulombs, F = 9.5×10⁻¹⁵ Newtons, B = 2.2×10⁻¹ Tesla

Substitute into equation 2

v = 9.5×10⁻¹⁵ /(5.2×10⁻¹⁹×2.2×10⁻¹)

v = 8.3×10⁴ m/s

v = 83000 m/s

0.11 m/s and 0.28 m/s should be correct