Physics, 22.04.2020 22:13 erinolson07cats

Wave motion is characterized by two velocities: the velocity with which the wave moves in the medium (e. g., air or a string) and the velocity of the medium (the air or the string itself). Consider a transverse wave traveling in a string. The mathematical form of the wave is y(x, t)=Asin(kx−ωt). a. Find the speed of propagation vp of this wave. b. Find the y velocity vy(x, t) of a point on the string as a function of x and t.

Answers: 2

Show answers

Answers

Answer from: alyssams4148

(a) The speed of propagation of the wave is $\frac{\omega}{k}$

(b) (b) The velocity of a point on the string as a function of x and t is $v_y (x, t) = -A\omega cos(kx - \omega t)$

The given parameters;

$y(x, t) = Asin(kx - \omega t)$

where;

t is the time of motiony is the displacement k is the wave number ω is the angular frequency A is the amplitude of the wave

(a) The speed of propagation of the wave is calculated as follows;

$v_p = \frac{\omega }{k}$

(b) The velocity of a point on the string as a function of x and t is calculated as follows;

$v = \frac{dy}{dt} \\\\v_y (x, t) = -A\omega cos(kx - \omega t)$

Learn more here:link

Answer from: morganluvsblueow9wtm

Answer with Explanation:

We are given that the mathematical form of wave

$y(x,t)=Asin(kx-\omega t)$

a.We have to find the speed of propagation of this wave

In given mathematical form

k=Wave number

$\omega$ =Angular frequency

A=Amplitude

We know that

Speed of propagation of the wave= $v_p=\frac{\omega}{k}$

b.Differentiate w.r.r t

$v_y(x,t)=-A\omega cos(kx-\omega t)$

The velocity v_y(x,t) of a point on the string as a function of x and t is given by

$v_y(x,t)=-A\omega cos(kx-\omega t)$

Answer from: Quest

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

$p(t)=0.3t^2+6t+80$

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

$p(0)=0+0+80=80$

according to question, we have said that if the population has twice its initial population, then it becomes

$p(t)=2\times 80=160$

so, time taken to reach this above mentioned population is given by

$160=0.3t^2+6t+80\\\\160-80=0.3t^2+6t\\\\80=0.3t^2+6t\\\\0.3t^2+6t-80=0\\\\\text{using quadratic formula ,we get }\\\\t_{1,\: 2}=\frac{-60\pm \sqrt{60^2-4\cdot \: 3\cdot \: 800}}{2\cdot \: 3}\\\\t=-29.14\ and\ t=9.149$

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

Answer from: Quest

Nps pollution is caused by rainfall or snowmelt moving over and through the ground. nonpoint source pollution can include: excess fertilizers, herbicides and insecticides from agricultural lands and residential areas. oil, grease and toxic chemicals from urban runoff and energy production

Another question on Physics

Physics, 22.06.2019 10:00

One object has a mass of 1 kg and another object has a mass of 3 kg. if the speeds are the same, which of the following is true about their kinetic energy?

Answers: 2

Answer

Physics, 22.06.2019 12:10

Does anyone have the answers to online physics course plato course physics, semester a v3.0

Answers: 2

Answer

Physics, 22.06.2019 17:30

Heterogeneous mixture with larger particles that never settle is

Answers: 2

Answer

Physics, 22.06.2019 17:40

Aball horizontally thrown from a cliff at 8m/s