El gas encerrado en un recipiente con las paredes rigidas esta a una presion de 150 000 Pa. La temperatura del gas es de 27°C A que temperatura en Kelvin y grados Celcius hay que calentar el gas para que la presion sea 300 000 Pa???

The gas enclosed in a container with rigid walls is at a pressure of 150,000 Pa. The temperature of the gas is 27 ° C. At what temperature in Kelvin and degrees Celcius does the gas have to be heated so that the pressure is 300,000 Pa?

Explanation:

Given that,

When the temperature is 27°C, it's pressure is 150,000 Pa

Then,

T₁ = 27°C

Let convert to Melvin

T₁ = 27 + 273 = 300K

P₁ = 150,000 Pa

What's the temperature when it is heated to a pressure of 300,000 Pa

T₂ =?

P₂ = 300,000 Pa

Since the gas is in a rigid wall container then the volume does not change so,

V₁ = V₂

Using Gay Lussac law,

P₁ / T₁ = P₂ / T₂

Making T₂ subject of formula

T₂ = P₂ × T₁ / P₁

T₂ = 300,000 × 300 / 150,000

T₂ = 600K

So, converting to °C

°C = K - 273

°C = 600 - 273

°C = 327 °C

Then, the final temperature at 300,000 Pa is 600K OR 327°C

So, using Spanish

Dado que,

Cuando la temperatura es de 27 ° C, su presión es de 150,000 Pa

Entonces,

T₁ = 27 ° C

Deje convertir a Melvin

T₁ = 27 + 273 = 300K

P₁ = 150,000 Pa

¿Cuál es la temperatura cuando se calienta a una presión de 300,000 Pa?

T₂ =?

P₂ = 300,000 Pa

Como el gas está en un contenedor de pared rígido, el volumen no cambia,

V₁ = V₂

Usando la ley Gay Lussac,

P₁ / T₁ = P₂ / T₂

Hacer T₂ sujeto de fórmula

T₂ = P₂ × T₁ / P₁

T₂ = 300,000 × 300 / 150,000

T₂ = 600K

Entonces, convirtiendo a ° C

° C = K - 273

° C = 600 - 273

° C = 327 ° C

Entonces, la temperatura final a 300,000 Pa es 600K o 327 ° C

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