A cylindrical insulated wire of diameter 5.0 mm is tightly wound 200 times around a cylindrical core to form a solenoid with adjacent coils touching each other. When a 0.10 A current is sent through the wire, what is the magnitude of the magnetic field on the axis of the solenoid near its center

0.0016 T

Explanation:

Parameters given:

Diameter of wire = 5 mm = 0.005 m

Radius of wire, R = 0.0025 m

Number of turns, N = 200

Current through the wire, I = 0.10A

The magnitude of the magnetic field is given as:

B = (u₀NI) / (2πR)

Where u = magnetic permeability of free space.

B = (1.257 * 10⁻⁶ * 200 * 0.1) / (2 * π * 0.0025)

B = 0.0016 T

The magnitude of the Magnetic field is 0.0016 T.

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