A uranium nucleus is traveling at 0.94 c in the positive direction relative to the laboratory when it suddenly splits into two pieces. Piece A is propelled in the forward direction with a speed of 0.43 c relative to the original nucleus. Piece B is sent backward at 0.34 c relative to the original nucleus. Find the velocity of piece A as measured by an observer in the laboratory. Do the same for piece B.

Answer with Explanation:

We are given that

Velocity of uranium=v=0.94 c

Speed of piece A relative to the original nucleus=

Speed of piece B relative to the original nucleus=

Velocity of piece A observed by observer

Substitute the values

Velocity of piece B observed by observer

The velocity of piece A and piece B as measured  by an observer in the laboratory are not same.

none, its a machine

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explanation: