A proton of mass mp is released from rest just above the lower plate and reaches the top plate with speed vp. An electron of mass me is released from rest just below the upper plate. Calculate the speed ve of the electron when it reaches the bottom plate, in terms of vp, mp, me, and physical constants, as appropriate. Ignore gravitational effects.

Explanation:

You can consider that the force that acts over the proton is the same to the force over the electron. This is because the electric force is given by:

where E is the constant electric field between the parallel plates, and is the same for both electron and proton. Also, the charge is the same.

by using the Newton second law for the proton, and by using kinematic equation for the calculation of the acceleration you can obtain:

(it has been used that vp^2 = v_o^2+2ad) where d is the separation of the plates, ap the acceleration of the proton, vp its velocity and mp its mass.

By doing the same for the electron you obtain:

we can equals these expressions for both proton and electron, because the forces qE are the same:

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.