) 37.36 .. Electrons are accelerated through a potential difference of 750 kV, so that their kinetic energy is 7.50 * 105 eV. (a) What is the ratio of the speed v of an electron having this energy to the speed of light, c? (b) What would the speed be if it were computed from the principles of classical mechanics?

(a) the ratio of the speed of an electron, v having this energy to the speed of light is 0.914 c

(b) the speed of the electron is 5.136 x 10⁸ m/s

Explanation:

Given;

potential of the electron, V = 750 kV

kinetic energy of the electron, K.E =  7.50 * 10⁵ eV

Part (A) the ratio of the speed of an electron having this energy to the speed of light

E = k + mc²

where;

E is the total energy of the electron

k is kinetic energy

Part (B) speed of the electron when computed from principles of classical mechanics

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the components of a vector are the parts of the vectors that are to each other.

b perpendicular