A barefoot field-goal kicker imparts a speed of 54 m/s to a football initially at rest. If the football has a mass of 0.55 kg and the time of contact with the ball is 0.033 s, what is the magnitude of the force exerted by the ball on the kicker’s foot? Answer in units of N.

Force, F = 900 N

Explanation:

Given that,

Mass of the football, m = 0.55 kg

Initial speed of the ball, u = 0

Final speed, v = 54 m/s

Time of contact, t = 0.033 s

We need to find the magnitude of the force exerted by the ball on the kicker’s foot. It is a case of second law of motion. It is equal to the rate of change of momentum. So,

So, the magnitude of the force exerted by the ball on the kicker’s foot is 900 N.

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

there are no contact forces mentioned on the list of choices that you've provided.