A dental X-ray typically affects 194 g of tissue and delivers about 3.6 μJ of energy using X-rays that have wavelengths of 0.033 nm. What is the energy E photon , in electron volts, of X-ray photons? E photon = eV How many photons are absorbed during the dental X-ray? Assume the body absorbs all of the incident X-rays. number of photons absorbed: photons/s

The energy of the photon in eV is gotten as; E = 37599.3 eV

The number of photons absorbed during the dental x-ray is; n = 5.976 × 10^(8) photons

We are given;

Mass of the affected tissue; m = 194 g = 0.194 kg

Energy delivered by dental x-ray; E = 3.6 μJ = 3.6 × 10^(-6) J

Wavelength; λ = 0.033 nm = 0.033 × 10^(-9) m

Formula for energy of a photon is given as;

E = hc/λ

Where;

h is Planck's constant = 6.626 × 10^(-34) J.s

c is speed of light = 3 × 10^(8) m/s

Thus;

E = (6.626 × 10^(-34) × 3 × 10^(8))/(0.033 × 10^(-9))

E = 6.0236 × 10^(-15) J

Now, let's convert the energy to eV.

From conversion calculator online, we have;

E = 37599.31 eV

Now, to get the number of photons absorbed during the dental x-ray, we will use the formula;

n = (energy delivered by dental x-ray)/(energy delivered to a single photon)

Thus;

n = (3.6 × 10^(-6))/(6.0236 × 10^(-15))

n = 5.976 × 10^(8) photons

Read more about energy of photons at; link

mistakes are ok

need to see circuit to get time constant