Physics, 21.04.2020 18:56 Maxwell2539
The lens-makers’ equation applies to a lens immersed in a liquid if n in the equation is replaced by n2/n1. Here n2 refers to the index of refraction of the lens material and n1 is that of the medium surrounding the lens. (a) A certain lens has focal length 79.0 cm in air and index of refraction 1.55. Find its focal length in water. (b) A certain mirror has focal length 79.0 cm in air. Find its focal length in water.
Answers: 2
![\frac{1}{f} = (n -1) [\frac{1}{R_1} - \frac{1}{R_2} ]](/tpl/images/0615/2728/7d9ee.png)
is the focal length 
is the index of refraction 
are the radius of curvature of sphere 1 and 2 of the lens![\frac{1}{f_{air}} = (n-1) [\frac{1}{R_1} - \frac{1}{R_2} ]](/tpl/images/0615/2728/05fbc.png)
![\frac{1}{f_{water}} = [\frac{n_2}{n_1} - 1 ] [\frac{1}{R_1} - \frac{1}{R_2} ]](/tpl/images/0615/2728/8672d.png)
![\frac{f_water}{f_{air}} = \frac{n_2 -1}{[\frac{n_2}{n_1} - 1] }](/tpl/images/0615/2728/42a8b.png)
= 79.0 cm
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