A cylindrical fishing reel has a mass of 0.7 kg and a radius of 5.24 cm. A friction clutch in the reel exerts a restraining torque of 1.88 N · m if a fish pulls on the line. The fisherman gets a bite, and the reel begins to spin with an angular acceleration of 65.7 rad/s 2 . What force does the fish exert on the line? Answer in units of N.

Explanation:

moment of inertia of reel = 1/2 mr² , m is mass and r is radius of the reel

= .5 x .7 x .0524²

= 96.1 x 10⁻⁵

If force required be F

F  x .0524 - 1.88 is net torque acting on the reel

F  x .0524 - 1.88 = moment of inertia x angular acceleration.

F  x .0524 - 1.88 = 96.1 x 10⁻⁵ x 65.7

F  x .0524 - 1.88 = .063

F  x .0524  = .063 + 1.88

F = 37.08 N

it has to be b, about 97 percent.

that would be because of both gravity and friction. so     c