Suppose that 3.00 g of hydrogen is separated into electrons and protons. Suppose also that the protons are placed at the Earth's North Pole and the electrons are placed at the South Pole. What is the resulting compressional force on the Earth?

Explanation:

Atomic mass of hydrogen is 1 . so 1 g of hydrogen will have 6.02 x 10²³ atoms

3 g of hydrogen will have 3 x 6.02 x 10²³ atoms . This will give 3 x 6.02 x 10²³  protons and same number of electrons

So number of protons at north pole = 3 x 6.02 x 10²³

charge on these protons = 1.6 x 10⁻¹⁹ x  3 x 6.02 x 10²³ C

= 28.9 x 10⁴ C  

similarly total charge on electrons at south pole = 28.9 x 10⁴ C

distance between them = diameter of the earth = 2 x 6356 x 10³ m

= 12712 x 10³ m

Attractive force between these charges

= k q₁q₂ / r² , q₁ ,q₂ are charges and r is distance between charges.

= 9 x 10⁹ x (28.9 x 10⁴)² / (12712 x 10³ )²

= 4.6517 x 10⁻⁵ x 10¹¹

= 4.6517 x 10⁶ N

the average speed is 24.57 km/hr

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)