A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.
What is the magnitude of the torque on the current loop?

The magnitude of the torque on the current loop is 0.0055 Nm

Explanation:

Given data,

We  have the formula,

T= u x B

Where u=  i x A

T= i×A×B ×sin(30)

T=0.46×0.52² ×0.900×0.5

T=0.0055 Nm

The magnitude of the torque on the current loop is 0.0055 Nm

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