Consider the inelastic collision. Two lumps of matter are moving directly toward each other. Each lump has a mass of 1.500 kg 1.500 kg and is moving at a speed of 0.930 c 0.930c . The two lumps collide and stick together. Answer the questions, keeping in mind that relativistic effects cannot be neglected in this case. What is the final speed v f vf of the combined lump, expressed as a fraction of c ?

The final velocity after impact of the combine lump is

V=0.930m/s

Explanation:

Step one

This type of collision is an inelastic types of collision. The total energy of the colliding bodies is conserved or when the bodies stick together and move with a common velocity

Step two

Given data

M1= 1500kg

M2=1500kg

U1=0.930m/s

U2=0.930m/s

V= ?

Step three

Applying momentum equation we have

Total momentum before impact

=M1U1+M2U2

Total momentum after impact

=(M1+M2) V

According to the principle of conservation of momentum

M1U1+M2U2=(M1+M2) V

Substituting our data into the expression we have

1500*0.930+1500*0.930=

(1500+1500)V

1395+1395=3000V

2790=3000V

V=2790/3000

V=0.930m/s

pretty sure it's false

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.