18,000 KG car is parked at the top of the hill 4.7 M have the car‘s brakes fail and it runs down the hill at the bottom of the hill what is the potential energy of the car

Is this a question of an answer

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

+10 that is always the common denominator

Wouldnt it be millileter