A particle hangs from a spring and oscillates with a period of 0.2s. If the mass-spring system remained at rest, by how much would themass stretch it fromits normal equilibrium position? The acceleration of gravity is 9.8m/s2.1. 0.00992948 m2. 0.0397179 m3. 0.019859 m4. 0.0311944 m5. 0.0794358 m6. 0.158872 m

The distance the mass would stretch it is    

The correct option is A

Explanation:

From the question we are told that

           The period of the slit is

           The acceleration due to gravity is

Generally the period is mathematically represented as

          Whee m is the particle and k is the spring constant

        making the subject

The weight on the particle is related to the force stretching the spring by this mathematical relation

where x is the length by which the spring is stretched

Substituting the equation above for

making x the subject

Substituting the value

that would be b i just took the test : )

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge