The gap between electrodes in a spark plug is d, 0.05 cm (not meters). To produce an electric spark in a gasoline-air mixture, there must be an electric field, E, of 3.5 x 10^6 V/m. What minimal potential difference, V, must be supplied by the ignition to start a car

The voltage that must be supplied is

V=1750volts

Explanation:

Step one :

The formula for the electric field between the charges is given by

E=V/d

Where E= the electric field

V= voltage or potential difference

d= the distance between the two electrodes

Step two :

Given that

E=3.5*0^6v/m

d=0.05cm to meter we have 0.0005m

V= unknown

By making v subject of formula we can solve for the required voltage

V=d*E

V=0.0005*3.5*10^6

V=1750volts