A loop of wire with a weight of 0.55 N is oriented vertically and carries a current I = 2.25 A. A segment of the wire passes through a magnetic field directed into the plane of the page as shwon. The net force on the wire is measured using a balance and found to be zero. What is the magnitude of the magnetic field?

Incomplete question.

Check the diagram given in attachment

Explanation:

Given that,

Weight w= 0.55N

Current I = 2.25A

Length = 0.2m

The net force is 0 N

Apply Newton second law

Fnet = ΣF

ΣF = 0

The weight is acting downward outside the plane

Then,

Magnetic Force — Weight = 0

F — W = 0

F = W

Magnetic force is given as

F = iLB

Therefore

iLB =W

B = W / iL

B = 0.55 / (2.25 × 0.2)

B = 1.22 T

The magnitude of the magnetic field is 1.22 T

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.