Wo bars are conducting heat from a region of higher temperature to a region of lower temperature. The bars have identical lengths and cross-sectional areas, but are made from different materials. In the drawing they are placed "in parallel" between the two temperature regions in arrangement A, whereas they are placed end to end in arrangement B. In which arrangement is the heat that is conducted the greatest?

Explanation:

Use radiant energy formula according for Stefan-Boltzmann law,

Qnet/t = AeσT4

Qnet is radiant energy, t is time, σ is Stefan constant, e is emissivity , A is cross sectional area and T is temperature.

Qnet(A)/t = (L0)2eσ(4T0)4 = 256L02eσT04

Qnet(B)/t = (2L0)2eσ(3T0)4 = 85L02eσT04

Qnet(C)/t = (3L0)2eσ(2T0)4 = 25L02eσT04

Thus, Qnet(A)/t > Qnet(B)/t > Qnet(C)/

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

cant without the picture! ?