[UColorado] Kepler's 3rd law: p^2 =a^3 for all planets. The period p for the earth is 1 year The distance of the earth to the sun is called 1 A. U. Suppose an asteroid is in circular orbit around the sun at a distance of 2 A. U. How long does it take the asteroid to orbit the sun once?

Explanation:

Given the Kepler's third law

p² = a³

Given that,

Period of earth

P(earth) = 1 year

Distance of earth from sun

a(earth) = 1 A.U

An asteriod that is rotating round the sun is at a distance of 2A.U for the sun

a(asteroid) = 2 A.U

So, we want to calculate period of astronaut I.e. p(asteroid)

Using the Keplers law

p²/a³ = constant

p(earth)²/a(earth)³ = p(asteriod)²/a(asteroid)³

So, p(e)²/a(e)³ = p(a)²/a(a)³

1²/1³ = p(a)²/2³

1 = p(a)/8

p(a) = 8 years

Then, the asteroid will take 8years to round the sun

volleyball players can not touch the net while the ball is in play

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this