An object acted on by three forces moves with constant velocity. One force acting on the object is in the positive xx direction and has a magnitude of 6.9 N; a second force has a magnitude of 4.5 N and points in the negative y direction. Find the direction and magnitude of the third force acting on the object.

Answer with Explanation:

We are given that

We have to find the direction and magnitude of the third force acting on the object.

Resultant force,F=

The object moves with constant velocity .Therefore, net force on object is equal to zero

So,Third force,

Direction,

Angle lies in second quadrant because the direction of third force is opposite to the direction of the resultant force of F1 and F2.

Therefore,

lexy is right because she has the labeled s

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