A piece of copper wire is formed into a single circular loop of radius 13 cm. A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to 0.86 T in a time of 0.67 s. The wire has a resistance per unit length of 4.4 x 10-2 /m. What is the average electrical energy dissipated in the resistance of the wire? Number Units

0.07 J

Explanation:

Parameters given:

Radius of loop, r = 13 cm = 0.13 m

Change in magnetic field, B = 0.86 T

Time taken, t = 0.67 s

Resistance per unit length of wire, R/L =

Resistance in the entire length of wire, R = R/L * L (where L = circumference of wire)

R =

R = 0.036 ohms

Electrical energy is given as the product of Power and Time;

E = P * t

Electrical power, P, is given as:

where V = EMF/Voltage

The average EMF induced in a coil is given as:

where A = Area of coil = =

Therefore, Power becomes:

Then, Electrical energy becomes:

The average electrical energy dissipated in the resistance of the wire is 0.07 J

their crystal patterns have been disrupted by stress

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement