Charge is distributed uniformly along a long straight wire. The electric field 2.00 cm from the wire is 20.0 NC/ directed radially inward towards the axis of symmetry. The linear charge density on the wire is

4. 50x10= 500m/s 5. 52m/s

Ithink it’s 98 because jajajjajansmsmjs

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j