Acar starts from rest at a stop sign. it accelerates at 4.0 m/s^2 for 3 seconds, coasts for 2 s, and then slows down at a rate of 3.0 m/s^2 for the next stop sign. determine the distance between the two stop signs.

Answer

66m

Explanation
This question will involve the three linear equations
1st v=at+u
2nd s=ut+1/2at²
3rd v²=u²+2as

Distance for part 1
s=ut+1/2at²
  =0×3 + 1/2×4×3²
  = 18m

Distance for part 2
v=at+u
  =4×3 +0
  =12
distance = speed × time
              =12×2
              = 24m
Distance for part 3
v²=u²+2as
0=12²-2×3×s
144 = 6s

s = 144/6
   = 24

total distance = 18+24+24
                      = 66m