What is the reaction that corresponds to the first ionization energy of rubidium

Rb(g) → Rb⁺(g) + e⁻    I₁ = 1st ionization energy

Explanation:

Here we have

Rb(g) → Rb⁺(g) + e⁻

The equation is of the form

X → X⁺ + e⁻

An atom that is made up of more than one electron requires a steadily  increasing amount of energy to remove each successive electron. The ionization energy I₁ to remove the first electron is the first ionization energy, which can be defined as follows

E(g) → E⁺(g)+ e⁻    I₁ = 1st ionization energy

Similarly, the second ionization energy  is given by

E⁺(g) → E²⁺(g) + e⁻    I₂ = 2nd ionization energy and so forth.

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas

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